Find the greatest number that can divide 3260 and 1471 leaving remainder 2 and 5 respectively
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Answer:
for no number it is possible
Step-by-step explanation:
for this we need to find hcf of (3260-2 and 1471-5)
that is hcf of 3258 and 1466 which is 2
but when we divide 3260 we get remainder 0 instead of 2 and when we divide 1471 by 2 we get remainder as 1 instead of 5
therefore it's not possible for any number
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