Find the greatest number that can divide 342,450 and 540, leaving no remainder 7 in each case.
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What you want is the HCF of
540 = 2x2x3x3x3x5
315 = 3x3x5x7
360 = 2x2x2x3x3x5
HCF = 3x3x5 = 45
So 45 is the largest numbers that will divide 540, 315 and 360.
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