Find the greatest number that divide 74 170 and 106 leaving a a remainder of 10 in each case
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Answered by
32
Answer:
74-10=64
170-10=160
106-10=96
The greatest number will be the HCF of 64,160,96
64=2*2*2*2*2*2
160=2*2*2*2*2*5
96=2*2*2*2*2*3
HCF=2*2*2*2=16
So, the greatest number is 16
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1
Answer:
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Step-by-step explanation:
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