Math, asked by gurleenuppal1101, 6 months ago

find the greatest number that divides 1200,216,312and leaves5,9,13as remainders respectively,is the question​

Answers

Answered by hp12345678
0

Answer:

1200216312 is a correct answer

Answered by bl4ze15
1

Answer:

On dividing 398 by the required number, there is a remainder of 7. This means that 398 7 = 391 is exactly divisible by the required number. Similarly, 436 -11 = 425 and 542 15 = 527 are exactly divisible by the required number. The HCF of two positive integers is the largest positive integer that divides both the integers.

Step-by-step explanation:

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