find the greatest number that divides 14, 27 and 40 leaving the remainder 2 ,3 and 4 respectively.
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Answered by
5
Answer:
Number = 12
Step-by-step explanation:
the greatest number that divides x, y and z leaving the remainder r1 , r2 and r3 respectively.
Number = HCF of (x-r1) (y-r2) (z-r3)
the greatest number that divides 14, 27 and 40 leaving the remainder 2 ,3 and 4 respectively.
Number = HCF of (14-2) (27-3) (40-4) = HCF of 12, 24, 36 = 12
Answered by
0
Answer:
12
Step-by-step explanation:
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