Question

Find the greatest number that divides 16137, 27225 and 25209 leaving 9 as a
remainder.​

Answer 1

Answer:

9

Step-by-step explanation:

first subtract 9 from 25209 then u get 25200

find HCF for these three numbers;

HCF for 16137,27225,25200is 9

Answer 2

1008 is the greatest number that divides 16137, 27225 and 25209 leaving 9 as a  remainder

Solution:

We have to find the greatest number that divides 16137, 27225 and 25209 leaving 9 as a  remainder

Subtract 9 from each number

16137 - 9 = 16128

27225 - 9 = 27216

25209 - 9 = 25200

Find the greatest common factor of 16128 , 27216 , 25200

$16128 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 7 \\\\27216 = 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3 \times 7 \\\\25200 = 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 5 \times 7$

Thus,

$HCF = 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 7 \\\\HCF = 1008$

Thus 1008 is the greatest number that divides 16137, 27225 and 25209 leaving 9 as a  remainder

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