Math, asked by nimmi99, 8 months ago

Find the greatest number that
divides 269 & 330 which leaves
a remainder 6 en each case​

Answers

Answered by cutepanda00123
1

Step-by-step explanation:

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.

Consider HCF be x.

In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.

609 = 3 x 3 x 29

957= 3 x 11 x 29

⇒ x = 3 x 29 = 87

∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

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