Find the greatest number that divides 27, 41 and 50 leaving 3, 5 and 2 respectively as remainder
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Step-by-step explanation:
27-3 = 24
41-5 = 36
50-2 =48
now find the HCF
24=6×2×2
36= 6×2×3
48= 6×2×4
so here the common factor is 6 and 2
hence, 6×2 = 12
thus, 12 is your answer
hope it's helpful for you!!!
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