Question

Find the greatest number that divides 33 and 45 leaving 3 as remainder

Answer 1

15 is answer mate

Step-by-step explanation:

33–3 = 30

168–3 = 165

Prime factors of

30 = 2x3x5

165 = 3x5x11

HCF = 3x5 = 15.

So the answer is 15.

Check: 33/15 = 2 as quotient and 3 as remainder. Correct.

168/15 = 11 as quotient and 3 as remainder. Correct.

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Answer 2

Step-by-step explanation:

The greatest no. that divides 33 and 45 leaving 3 as remainder is :

1st no. be 33 - 3 = 30

2nd no. be 45 - 3 = 42

Now the HCF of (30,42) is: 6

So, the greatest no. that divides 33 and 45 leaving 3 as remainder is 6