Find the greatest number that divides 3960,4455,and 2970 without leaving any remainder
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18
Answer:
495
Step-by-step explanation:
We need to find highest common factor HCF of 3960,4455 and 2970
Let's get prime factors of each:
3960= 2^3 x 3^2 x 5 x 11
4455= 3^4 x 5 x 11
2970= 2 x 3^3 x 5 x 11
HCF(3960,4455,2970)= 3^2*5*11=495
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