find the greatest number that divides 47, 77 and 89 leaving the remainder 5 in each case
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Answered by
16
To find the largest number which divides 47.77and 89 leaving remainder 5in each case i.e. HCF.
Consider HCF be x.
In order to make 47 ,77 and 89 completely divisible by x, we need to deduct the remainder 5 from 47 ,77 and 89
47 - 5 =42
77 - 5=72
89 - 5=84
prime factors of the nos are-
42= 2 x 3 x 7
72 =2 x 2 x 2 x 3 x 3
84= 2 x 2 x 3 x 7
⇒ x = 2 x 3 = 6
HCF= 6
∴ the largest number which divides 47.77and 89 leaving remainder 5 in each case = 5 ans.
Answered by
1
Answer:
2×3=6
Step-by-step explanation:
72=2.2.2.3.3
42=2.3.7
84=2.2.3.7
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