Question

Find the greatest number that divides 56 , 72 ,140 without leaving a remainder

Answer 1

Answer:

greatest no. which divides 56,72,140 without leaving remainder=HCF(56,72,140)

56=2^3*7^1

72=2^3*3^2

140=2^2*5^1*7^1

Therefore , HCF=2^2=4....answer

Hope it helps u.... ^.^

Answer 2

The greatest number that divides 56, 72, 140 is their Highest Common Factor (HCF)

56 = 2 x 2 x 2 x 7
72 = 2 x 2 x 2 x 2 x 3 x 3
140 = 2 x 2 x 5 x 7

HCF = 2 x 2
HCF(56,72,140) = 4