Find the greatest number that divides 56 , 72 ,140 without leaving a remainder
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Answer:
greatest no. which divides 56,72,140 without leaving remainder=HCF(56,72,140)
56=2^3*7^1
72=2^3*3^2
140=2^2*5^1*7^1
Therefore , HCF=2^2=4....answer
Hope it helps u.... ^.^
iamarjunjayan:
Hcf is 4
Answered by
12
The greatest number that divides 56, 72, 140 is their Highest Common Factor (HCF)
56 = 2 x 2 x 2 x 7
72 = 2 x 2 x 2 x 2 x 3 x 3
140 = 2 x 2 x 5 x 7
HCF = 2 x 2
HCF(56,72,140) = 4
56 = 2 x 2 x 2 x 7
72 = 2 x 2 x 2 x 2 x 3 x 3
140 = 2 x 2 x 5 x 7
HCF = 2 x 2
HCF(56,72,140) = 4
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