find the greatest number That divides 74,112 and 152 leaving the remainders 2,4 and 6 respectively.
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Answered by
1
Answer:
Step-by-step explanation:
The number divides 74 and leaves 2 as remainder
∴ The number exactly divides 74 - 2 = 72
The number divides 112 and leaves 4 as remainder
∴ The number exactly divides 112 - 4 = 108
The number divides 152 and leaves 6 as remainder
∴ The number exactly divides 152 - 6 = 146
Now, we have to find HCF of 72,108,146
Find HCF of 72,108,146
1. Find HCF of (72,108)
HCF of (72, 108) = 36
2. Now find HCF of 36 and 3rd number 146
HCF of (36, 146) = 2
∴ HCF of 72,108,146=2
∴ Required number = HCF of 72,108,146=2.
Hope this helps!
Answered by
0
Answer:
simply and divide 150/74, 452/112 and 918/152
Step-by-step explanation:
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