Question

find the greatest number That divides 74,112 and 152 leaving the remainders 2,4 and 6 respectively.​

Answer 1

Answer:

Step-by-step explanation:

The number divides 74 and leaves 2 as remainder

∴ The number exactly divides 74 - 2 = 72

The number divides 112 and leaves 4 as remainder

∴ The number exactly divides 112 - 4 = 108

The number divides 152 and leaves 6 as remainder

∴ The number exactly divides 152 - 6 = 146

Now, we have to find HCF of 72,108,146

Find HCF of 72,108,146

1. Find HCF of (72,108)

HCF of (72, 108) = 36

2. Now find HCF of 36 and 3rd number 146

HCF of (36, 146) = 2

∴ HCF of 72,108,146=2

∴ Required number = HCF of 72,108,146=2.

Hope this helps!

Answer 2

Answer:

simply and  divide 150/74, 452/112 and 918/152

Step-by-step explanation: