Question

find the greatest number that divides 79,88 and 160 leaving remainder 7 in each case.​

Answer 1

Answer:

Hey mate here is the answer

Step-by-step explanation:

As 79,88 and 160 are divided with x where the remainder is 7

So , taking the numbers as:

79-7= 72

88-7= 81

160-7= 153

So in the numbers 72, 81, and 153 , (9) is common

So the answer x is 9

Hope it helps you

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Answer 2

$\begin{gathered}\begin{gathered}\Large\bold{\mathcal{\colorbox{yellow}{\blue{Solution:⤵}}}} \\ \large \bold{ \mathtt{ \colorbox{red}{ \blue{Given \: HCF=12,LCM=5040}}}} \\ \large \bold{ \mathcal{ \colorbox{pink}{ \pink{and also one number is 144}}}} \\ \large \bold{ \mathtt{ \colorbox{yellow}{ \blue{Let the other number be x}}}} \\ \large \bold { \mathtt{ \colorbox{orange}{{As we know that}}}} \\ \large \bold{ \mathtt{ \colorbox{navy}{ \orange{Product of two numbers is HCF×LCM}}}} \\ \large \bold{ \mathtt{ \colorbox{orange}{ \red{⟹144×x=12×5040}}}} \\ \large \bold{ \mathtt{ \colorbox{lime}{ \purple{⟹x=420}}}} \\ \large \bold{ \mathtt{ \colorbox{aqua}{ \red{So, The other number is 420}}}} \end{gathered}\end{gathered}$