Find the greatest number that divides 85 and 101 leaving remainder of 5 in each case.
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So,Your answer is 16.
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85-5=80
101-5=96
HCF of 80 and 96
80=2×2×2×2×5
96=2×2×2×2×2×3
Common factor=2×2×2×2=16
Therefore, 16 is the greatest number that divides 85 and 101 leaving remainder of 5 in each case.
Check=
16×5+5=80+5
16×6+5=96+5
Hope this helps you
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