Find the greatest number that will divide 121 ,33,and 55 leaving remainder 1,3,5 respectively
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ANSWER
Subtract the remainder from the number respectively then, take out the factors of the same as mentioned below.
121−1=120=2×2×2×3×5
33−3=30=2×3×5
55−5=50=2×5×5
H.C.F(120,30,50)=2×5=10
So, answer=10
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