find the greatest number that will divide 121,33 and 55 leaving 1,3 and 5, respectively, as remainders
Answers
Answered by
34
121-1=120
33-3=30
55-5=50
HCF of 120,30,50
=600
33-3=30
55-5=50
HCF of 120,30,50
=600
hammadashraf38pbd9wx:
find the HCF of 120,30 and 50 in detail.kindly
120=2*2*2*3*5 30=2*3*5 50=2*5*5
HCF=2*3*5
=30
there are two different answers?
600 and 30 how?
Answered by
23
subtract the remainders
then find HCF(120,30,50)=10
therefore the greatest number is 10 which divides 121 and 33 and 55 leaving 1and 3 and 5 as remainder
then find HCF(120,30,50)=10
therefore the greatest number is 10 which divides 121 and 33 and 55 leaving 1and 3 and 5 as remainder
Similar questions