Find the greatest number that will divide 1259, 1558 and 1935 leaving the same remainder in each case.
1)13
2) 15
3) 16
4) 12
5) 11
Answers
Answered by
2
Answer:
All three numbers are 1259, 1558, and 1935
The Largest number is 1935
The Smallest number is 1259
Subtract the smallest number from both the highest numbers.
So,
1935 - 1259 = 676
1558 - 1259 = 299
1558 is smaller than 1935, So subtract 1558 from 1935.
1935 - 1558 = 377
Now, we have 3 numbers: 676, 377, and 299.
So, the HCF of 676, 377, and 299. is 13
So,
The highest number that divides 1259, 1558 and 1935 and leaves the same remainder is 13.
Hope this helps
Similar questions