Math, asked by anmolj477, 6 months ago

Find the greatest number that will divide 129, 161, and 224 leavi6a remainder of 5,6 and 7 respectively​

Answers

Answered by paritoshmodak29535
0

Answer:

129 - 5 = 124

161 - 6 = 155

224 - 7 = 217

New numbers are 124 , 155 and 217.

Now,

Prime factorisation of 124 = 2 × 2 × 31

Prime factorisation of 155 = 5 × 31

Prime factorisation of 217 = 7 × 31

Required Number = HCF (125,155,217) = 31

Step-by-step explanation:

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