Find the greatest number that will divide 129, 161, and 224 leavi6a remainder of 5,6 and 7 respectively
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Answer:
129 - 5 = 124
161 - 6 = 155
224 - 7 = 217
New numbers are 124 , 155 and 217.
Now,
Prime factorisation of 124 = 2 × 2 × 31
Prime factorisation of 155 = 5 × 31
Prime factorisation of 217 = 7 × 31
Required Number = HCF (125,155,217) = 31
Step-by-step explanation:
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