find the greatest number that will divide 137,182,422 leaving the remainder 2 in each case
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The answer is 15
Hope so this was helpful
Hope so this was helpful
Aaryanyadav:
thanks , please send full process
Okh wait
Be my friend then I'll message you the process. As I'm not being able to send it in this . Okh
Answered by
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hye
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we have to find the greatest number that will divide 137,182,422 leaving the remainder 2 in each case
let the hcf be A
=> so let us subtract 2 from the 3 cases
=>137 - 2 =135
=> 182-2 = 180
=>422-2 = 420-------------------now lets find the hcf
=>prime factorisation of 135= 3*3*3*5
prime factoristaion of 180 = 2*5*2*3*3
prime factoristaion of 420 = 7*5*3*3*2
now lets take out the common factors from 3 cases
=> 3 and 5,
x = 5* 3 = 15
∴ 15 is the number that will divide 137,182,422 leaving the remainder 2 in each case
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hope it helps u.........
==============================
we have to find the greatest number that will divide 137,182,422 leaving the remainder 2 in each case
let the hcf be A
=> so let us subtract 2 from the 3 cases
=>137 - 2 =135
=> 182-2 = 180
=>422-2 = 420-------------------now lets find the hcf
=>prime factorisation of 135= 3*3*3*5
prime factoristaion of 180 = 2*5*2*3*3
prime factoristaion of 420 = 7*5*3*3*2
now lets take out the common factors from 3 cases
=> 3 and 5,
x = 5* 3 = 15
∴ 15 is the number that will divide 137,182,422 leaving the remainder 2 in each case
========================
hope it helps u.........
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