Math, asked by Manshikeisham, 1 year ago

Find the greatest number that will divide 1625,2281 and 4218 leaving the remainder 8,4and5 respectively

Answers

Answered by Anonymous
3

Answer:

》》》》》》》》

= 11

is the right answer

Answered by payalchatterje
0

Answer:

11 is the greatest number that will divide 1625,2281 and 4218 leaving the remainder 8,4and5 respectively.

Step-by-step explanation:

The number divides 1625,2281 and 4218 leaving the remainder 8,4 and 5.

So, that number will divide (1625-8), (2281-4),(4218-5) completely.

Therefore,that number will divide 1617, 2277,4213 completely.

Now, the greatest number that will divide 1617, 2277,4213 completely, is the H.C.F. of these numbers.

We know HCF means Highest Common Factor.

By prime factorisation,

1617 = 3 \times 7 \times 7 \times 11 \\ 2277 = 11 \times 3 \times3 \times  23 \\ 4213 = 11 \times 383

The highest common factor of 1617, 2277,4213 is 11.

So,HCF of 1617, 2277,4213 is 11.

Therefore,we can say that 11 is the greatest number that will divide 1625,2281 and 4218 leaving the remainder 8,4and5 respectively.

Know more about HCF,

https://brainly.in/question/25945206

https://brainly.in/question/20353612

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