Find the greatest number that will divide 328, 436 and 544 leaving remainder 7, 8 and 9 respectively
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Solution:
We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.
Now
→ 328 - 7 = 321
→ 436 - 8 = 428
→ 544 - 9 = 535
Now, we have to find the HCF of 321, 428, 535
- HCF of 321 = 3 × 107
- HCF of 428 = 2 × 2 × 107
- HCF of 535 = 5 × 107
107 is common in 321, 428 and 535.
So, HCF is 107
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107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively
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