find the greatest number that will divide 33 and 45 leaving a remainder 9 in each case
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The required number is HCF(33 - 9, 45 - 9) provided it is greater than 9
HCF(33 - 9, 45 - 9) = HCF(24, 36) = 12
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Answer will be 12 that will leave remainder 9 in each case...
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