. Find the greatest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively
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Correct Question:
Find the greatest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively
Solution :
We have to find the largest number that will divide 398, 436 and 542 Leaving the remainders 7, 11 and 15 .
We need to the hcf of 3 numbers
(398 - 7) , (436 - 11) , and (542-15)
Hence, the HCF is
398 - 7 = 391.
436 - 11 = 425 .
542 - 11 = 527 .
So, Hcf of (398,436,542) = 17.
Hence, the largest number which will divide by 398,436, 542 leaving remainders 7,11,and 15 respectively is 17.
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