find the greatest number that will divide 41,
,62,123 leaving remainder 1,2 and 3 respectively
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Answered by
0
The answer is 20.
Hope this helps!
Hope this helps!
NitinPetash:
no that's wrong
i have written the correct one
Answered by
1
for finding divisible no.
they will be .. 41-1,62-2,123-3
or 40,60 and 120
the required no. is their HCF
So, it is 20
they will be .. 41-1,62-2,123-3
or 40,60 and 120
the required no. is their HCF
So, it is 20
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