find the greatest number that will divide 43 91 and 183 leaving the same remainder in each case
Answers
Answered by
1
my answer is 4 l like it
Attachments:
Answered by
0
Answer:
4
Step-by-step explanation:
Here, we need to find differences between the given numbers. If two numbers give the same remainder when divided by some other number, then their difference must give a remainder of zero when divided by that number.
Our numbers here are 91−43=48,183−91=92,183−43=140
So we have the set of numbers {48,92,140} and we want to know the biggest number that divides all these numbers.
So,
48=2×2×2×3
92=2×2×23
140=2×2×5×7
The greatest common divisor of {48,92,140} is 4.
So, answer is 4.
Similar questions