Question

Find the greatest number that will divide 445,572 and 699 leaving remainder 4 , 5 and 6 respectively

Answer 1

hi

Find the greatest number that will divide 445,572 and 699 leaving remainder 4 , 5 and 6 respectively

445 - 4 = 441

572  - 5 = 567

699 - 6 = 693

so the numbers are 441,567 and 693

now let us find the hcf of 441,567 and 693

441 =  3 x 3 x 7 x 7 

567 = 3×3×3×3×7

693 = 3×3×7×11

hcf = 3×3×7

hcf = 63

hence 63 is the greatest number that will divide 445,572 and 699 leaving remainder 4 , 5 and 6 respectively

hope it helps u

:)

Answer 2

Heya !!!


445 - 4 = 441


572 - 5 = 567


699 - 6 = 693



New numbers are 441 , 567 and 693 .


Now,


Prime factorisation of 441 = 3 × 3 × 7 × 7


Prime factorisation of 567 = 3 × 3 × 3 × 3×7


Prime factorisation of 693 = 3 × 3 × 7 × 11



Required Number = HCF(441,567,693) = 3 × 3 × 7 = 63


Hence,


The greatest Number that Divides 445 , 572 and 699 leaves Remainder 4 , 5 and 6 is 63.



HOPE IT WILL HELP YOU....... :-)