find the greatest number that will divide 63,36 and 90 leaving remainder 9 in each case
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Step-by-step explanation:
Step-by-step explanation:
adding reminder 9 to all the numbers
i) 63 + 9 = 72
ii)36 + 9 = 45
iii)90 + 9 = 99
taking out prime factor s
i) 72 = 2×2×2×3×3
ii) 45 = 5×3×3
iii) 99 = 11×3×3
In this factors the HCF is 3×3 , i.e. 9
: . the required no. is 9
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