Question

Find the greatest number that will divide 76, 113 and 186 leaving remainders 4,5 & 6 respectively.

Answer 1

Answer:

(76-4),(113-5),(186-6) will exactly divisible by the required number

180=108X1+72

108=72X1+36

72=36x2+0.

36is HCF of 180and108

72=36x2+0

36 is HCF of 36and 72

so,

36 is the required number that divide 76, 113 and 186 leaving remainders 4,5 & 6 respectively.

THANKS!!!