Find the greatest number that will divide 80,118 and 60 leaving remainders 8 10 and 12 respectively.
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Answer:
The greatest number that will divide 80,118 and 60 leaving remainder 8,10 and 0 is 12.
Step-by-step explanation:
First of all, we subtract 8 from 80 we get 72.
then,118-10=108
at last, 60-0=60
And now we get HCF of 72,108 and 60
We get 12.
12 is the number which is divisble by 80,118,60 and remaining 8,10 and 0
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