Question

Find the greatest number that will divide each of 90,108 and 126 without leaving a remainder

Answer 1

Answer:

Find the HCF of 90, 108 and 126.

90 = 2x3x3x5

108 = 2x2x3x3x3

126 = 2x3x3x7

HCF = 2x3x3

Thus 18 is the greatest number that can divide 90, 108 and 126 without leaving a remainder.