Find the greatest number that will divide each of 90,108and126without leaving a remainder
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Answer:
Your answer is 18...
Step-by-step explanation:
90 = 2 × 3^2 × 5
108 = 90 + 9×2 = 3^2 × 12 = 2^2 × 3^3
126 = 90 + 9×4 = 3^2 × 14 = 2 × 3^2 × 7
The greatest number dividing 90,108,126 is the product of all the common prime factors:
2 : any multiple of greater powers of 2 will not divide 90
3^2 : any multiple of greater powers of 2 will not divide 90 and 126
gcd (90,108,126) = 2 × 3^2 = 18
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