Question

Find the greatest number that will divide each of 90,108and126without leaving a remainder

Answer 1

Answer:

Your answer is 18...

Step-by-step explanation:

90 = 2 × 3^2 × 5  

108 = 90 + 9×2 = 3^2 × 12 = 2^2 × 3^3  

126 = 90 + 9×4 = 3^2 × 14 = 2 × 3^2 × 7  

The greatest number dividing  90,108,126 is the product of all the common prime factors:

2 : any multiple of greater powers of  2  will not divide  90  

3^2 : any multiple of greater powers of  2  will not divide  90  and  126  

gcd (90,108,126) = 2 × 3^2 = 18

PLEASE MARK AS BRAINLIEST IF IT REALLY HELPS YOU...❣❣❣