Find the greatest number that will exactly divisible by1065 and 1491
Answers
Answered by
0
Answer:
213
Step-by-step explanation:
1491 = 1065 x 1 + 426; r is not = 0
1065 = 426 x 2 + 213 ; r is not = 0
426 = 213 x 2 + 0 ; r is = 0
hence HCF is 213
Similar questions
CBSE BOARD XII,
5 months ago
English,
5 months ago
English,
5 months ago
English,
1 year ago
English,
1 year ago