Find the greatest number which can divide 1354 ,1866 and 2762 leaving the same remainder 10 in each case
Answers
Subtracting 10 from each of the gievn numbers.
1354 - 10 = 1344
1866 - 10 = 1856
And,
2762 - 10 = 2752
Prime factorisation of 1344 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7
Prime factorisation of 1856 = 2 × 2 × 2 × 2 × 2 × 2 × 29
And,
Prime factorisation of 2752 = 2 × 2 × 2 × 2 × 2 × 2 × 43.
HCF of 1344 , 1856 and 2752 = 2 × 2 × 2 × 2 × 2 × 2 = 64.
Hence,
The greatest number which can divide 1354 , 1866 and 2762 leaving remainder 10 in each case is 64.
Answer:
The greatest number is 64 which can divide 1354,1866 and 2762 leaving the same remainder 10 in each case.
Step-by-step explanation:
Given numbers are 1354, 1866 and 2762
1354 - 10 = 1344
1866 - 10 = 1856
2762 - 10 = 2752
Find HCF of the numbers 1344, 1856 and 2752
HCF of 1344, 1856
1344) 1856( 1
1344
512) 1344( 2
1024
320) 512 ( 1
320
192) 320 ( 1
192
128) 192 ( 1
128
64) 128 ( 2
128
0
HCF of 64, 2752
64) 2752( 43
256
192
192
0
HCF of 1344, 1856, 2752 would be 64.
Answer would be 64.
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