Question

Find the greatest number which can divide 257 and 329 so as to leave a remainder 5 in each case.

Answer 1

Answer:

36

Step-by-step explanation:

So, the required number which when divides 257 and 329 and leaves remainder 5 will be HCF (252,324) ⇒ 2 × 2 × 3 × 3 = 36. So, the greatest number which when divides 257 and 329 leaves remainder 5 each time is 36

Answer 2

Answer:

First subtract 5 from those numbers and take common factors of the two numbers and multiply the common factors and you will get the answer.