Question

find the greatest number which can divide 257 and 329 so as to leave a remainder 5 in each case​

Answer 1

Answer:

257-5=252

329-5=324

From prime factorization,

252=2×2×3×3×7

=2^2×3^2×7

324=2×2×3×3×3×3

=2^2×3^4

HCF(252,324)=2^2×3^2

=4×9

=36