Find the greatest number which can divide 257 and 629 so as to leave a remainder 5 in each case.
Answers
Answered by
1
Answer:
according to the question we have to find the HCF of (257-5) and (629-5) i.e., 252 and 624
Step-by-step explanation:
252= 2*2*3*3*7
624= 2*2*2*2*3*13
HCF(252,624)= 2*2*3
= 12
Answered by
0
Answer:
252 and 624
Step-by-step explanation:
as 5 is the remainder therefore, the numbers must be 257 - 5 and 629 -5
on subtracting 5 in both the numbers, we get :
252 and 624
and also
on dividing 257 by 252 we get 5 as remainder and same is the case of 629/624
hope u understood
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