find the greatest number which can divide 89 53 and 77 and leave a remainder of 5 in each case
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The Greatest Number required is the HCF of 89, 53 and 77
Using Euclid's Division Lemma
a = bq+r
HCF(89,53)
-» 89 = 53 * 1 + 36
-» 53 = 36 * 1 + 17
-» 36 = 17 * 2 + 2
-» 17 = 2 * 8 + 1
-» 2 = 1 * 2 + 0
Therefore, HCF (89,53) = 1
Now, HCF( 89,53,77) = HCF( 1,77)
77 = 1 * 77 + 0
Therefore, HCF(89,53,77) = 1
Therefore, the highest number which divides the numbers 89,53,77 is 1
yugendran11:
wrong answer
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