Math, asked by anaisajain1, 9 months ago

Find the greatest number which divides 126 150 and 210 leaving remainder 6 in each case.

Answers

Answered by akilaram81
28

Answer:

Step-by-step explanation:

126-6=120

150-6=144

210-6=204

120=2*2*2*3*5

144=2*2*2*2*3*3

204=2*2*3*17

common factors are 2*2*3=HCF=12

126/12=Quotient=10 Remainder=6

150/12=Quotient=12 Remainder=6

210/12=Quotient=17 Remainder=6

Answered by maneetsingh423
3

Answer:

Thanks for the answer answer was good

Similar questions