Math, asked by manju01lamba, 13 hours ago

find the greatest number which divides 126 150 and 210 leaving remainder 6 in each case ​

Answers

Answered by dg7225889
5

Answer:

Find the greatest number which divides 126, 150 and 210 leaving remainder 6 in each case.

a)12

b)14

c)16

d)22

Correct answer is option 'A'. Can you explain this answer?

Answered by COMMANDED
2

Answer:

Correct option is A)

we have to find the largest number which divide 615 and 963 leaving remainder 6 in each case.

so let us subtract 6 from 615 and 963

⇒ 615−6=609

⇒ 963−6=957

now lets find the HCF

⇒ prime factorisation of 609=29×3×3

prime factorisation of 957=29×3×11

now lets take out the common factors from both the cases

⇒ 29 and 3

x=29×3=87

∴ 87 is the number which will divide 615 and 963 leaving remainder 6 in each case.

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