Question

find the greatest number which divides 127 and 161 leaving remainders 7 and 5

Answer 1

We will subtract 7 and 5 from 127 and 161


127 - 7 = 120

161 - 5 = 156


Now, we will find the HCF of 120 and 156


120 = 2 × 2 × 2 × 3 × 5

156 = 2 × 2 × 3 × 13

Common factor = 2 × 2 × 3

= 12


$\therefore{}$ The number is 12

Answer 2

❤❤Here is your answer ✌ ✌

$\huge {\red {\bold {Answer}}}$

1st step:-

We will subtract 7 and 5 from 127 and 161


127 - 7 = 120

161 - 5 = 156

2nd step:-

Now, we will find the HCF of 120 and 156


120 = 2 × 2 × 2 × 3 × 5

156 = 2 × 2 × 3 × 13

Common factor = 2 × 2 × 3

= 12


so,The number is 12