find the greatest number which divides 137 ,167 and 152 leaving a remainder 2 in each case.
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Answered by
27
hi
aim: to find the greatest number which divides 137 ,167 and 152 leaving a remainder 2 in each case.
=> 137 - 2 = 135
167 - 2 = 165
152 - 2 = 150
so the obtained numbers are 135 :165 and 150
now let us find their hcf
135 = 1,3,5,9,15,27,45,135
165 = 1, 3, 5, 11, 15, 33, 55, 165
150 = 1,2,3,5,6,10,15,25,30,50,75,150
hcf = 15
hence 15 is the the greatest number which divides 137 ,167 and 152 leaving a remainder 2 in each case.
hope it helps u
:)
aim: to find the greatest number which divides 137 ,167 and 152 leaving a remainder 2 in each case.
=> 137 - 2 = 135
167 - 2 = 165
152 - 2 = 150
so the obtained numbers are 135 :165 and 150
now let us find their hcf
135 = 1,3,5,9,15,27,45,135
165 = 1, 3, 5, 11, 15, 33, 55, 165
150 = 1,2,3,5,6,10,15,25,30,50,75,150
hcf = 15
hence 15 is the the greatest number which divides 137 ,167 and 152 leaving a remainder 2 in each case.
hope it helps u
:)
Dristy111:
haan
Answered by
16
Answer:
The required largest number is 15.
Step-by-step explanation:
Given : The greatest number which divides 137 ,167 and 152 leaving a remainder 2 in each case.
To find : The number ?
Solution :
First we find the difference between numbers. and reminder.
The required numbers are
137-2=135
167-2=165
152-2=150
Now, We find the HCF of 135,165 and 150.
Therefore, The required largest number is 15.
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