Math, asked by sharath6076, 11 months ago

Find the greatest number which divides 148 and hundred leaving remainder 4 in each case

Answers

Answered by mhanifa

3

Answer:

48

Step-by-step explanation:

Numbers fit the condition:

148=ax+4 => ax=144

100=bx+4 => bx=96

Prime factors of 144 and 96:

144=2*2*2*2*3*3

96=2*2*2*2*2*3

HCF(144,96)=48

Answer is 48

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