find the greatest number which divides 149 and 101 leaving remainder 5 in each case
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Answer is 12 because dived with 12 than remainder will remain 5 in both case
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Greatest number is 48 which divide 149 and 101 leaving remainder 5 in each case
as it says that it leave 5
149-5=144
101-5=96
HcF of 144 and 96 is 48 so I knew
as it says that it leave 5
149-5=144
101-5=96
HcF of 144 and 96 is 48 so I knew
pratyush4211:
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