Find the greatest number which divides 149 and101 leaving remainder 5 in each case
Answers
Answered by
2
I hope you can understand this
Attachments:
bharat9291:
sorry the hcf will be 48
Answered by
4
149-5 101-5
=144,96
LCM of 144=2x2x2x2x3x3
LCM of 96=2x2x2x3
2 and 3 are left out so we multiply them
2x3=6
Therefore 6 is the no which when multiplied to 149 and 101 leaves a remainder of 5
sir you are doing it by wrong method .please check your method
Similar questions