Question

Find the greatest number which divides 2011 and 2423 leaving remainders 9 and 5 respectively

Answer 1

Numbers are2011 and2423 leaving remainder9 and 5 respectively
2011-9 =2002
2423-5 =2418
Now finding hcf
2002 = 2*7*11*13
2418 =2*3*13*31
HCF = 13*2= 26 greatest number = 26

Answer 2

We have to find the HCF of
(2011-9=2002) and
(2623-5=2423)

Therefore factors of
2002=2×7×11×13
2618=2×7×11×17

Therefore HCF is 2×7×11=154

2011÷154
Quotient=13... Remainder=9

2623÷154
Quotient=17... Remainder=5




I guess your question is misprinted/mistyped .

Thank you.