find the greatest number which divides 2011 and 2623 leaving remainder 9 and 5 respectively in each case
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The formula =>
Dividend = ( Divisor × Quotient ) + Remainder
Dividend in first place = 2011 , remainder = 9
2011 = ( Divisor × Quotient ) + 9
Divisor × Quotient = 2011 - 9 = 2002
Now, list out the factors
2 × 7 × 11 × 13
The second dividend
Apply the same formula
we get,
Divisor × Quotient = 2618
List out the factors
2 × 7 × 11 × 17
HCF is 2 × 7 × 11
HCF is 154
Divisor is 154
Now, the first one
Divisor × Quotient = 2002
154 × Quotient = 2002
Quotient = 2002/154
Quotient = 13
The second one
Divisor × Quotient = 2618
154 × Quotient = 2618
Quotient = 17
First one , and second one
Dividend = 2011 , 2623
Divisor = 154 , 154
Remainder = 9 , 5
Quotient = 13 , 17
Dividend = ( Divisor × Quotient ) + Remainder
Dividend in first place = 2011 , remainder = 9
2011 = ( Divisor × Quotient ) + 9
Divisor × Quotient = 2011 - 9 = 2002
Now, list out the factors
2 × 7 × 11 × 13
The second dividend
Apply the same formula
we get,
Divisor × Quotient = 2618
List out the factors
2 × 7 × 11 × 17
HCF is 2 × 7 × 11
HCF is 154
Divisor is 154
Now, the first one
Divisor × Quotient = 2002
154 × Quotient = 2002
Quotient = 2002/154
Quotient = 13
The second one
Divisor × Quotient = 2618
154 × Quotient = 2618
Quotient = 17
First one , and second one
Dividend = 2011 , 2623
Divisor = 154 , 154
Remainder = 9 , 5
Quotient = 13 , 17
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