Question

find the greatest number which divides 2011 and 2623 leaving remainder 9 and 5 respectively
step by step​

Answer 1

Answer:

Hey here is the answer

Step-by-step explanation:

2011–9 = 2002

2623–5 = 2618.

Factors of

2002 = 2 x7x11x13

2618 = 2x7x11x17

The HCF = 2 x7x11 = 154.

Check: 2011/154 = quotient = 13, and remainder = 9. Correct.

2623/154 = quotient = 17, and remainder = 5. Correct.

The number is 154.

Answer 2

Answer:

154

This is your answer ☝

Step-by-step explanation:

let n divides 2011 and 2623 leaving the remainder 9,5 respectively

then 2011 can be expressed as 2011 = n p + 9

n p = 2011-9

=2002

n p = 2*7*11*13

2623 can be expressed as 2623 = n q + 5

n q =2623-5

=2618

n q = 2*7*11

p = 13

q = 17

n=2*7*11

= 154