Find the greatest number which divides 2011 and 2623 leaving remainder 9 and case of five each
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2011–9 = 2002
2623–5 = 2618.
Factors of
2002 = 2 x7x11x13
2618 = 2x7x11x17
The HCF = 2 x7x11 = 154.
Check: 2011/154 = quotient = 13, and remainder = 9. Correct.
2623/154 = quotient = 17, and remainder = 5. Correct.
The number is 154.
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