Math, asked by shimlarajput3022, 7 months ago

Find the greatest number which divides 2011b and 2623 , leaving remainders 9 and5 respectively.

Answers

Answered by Anonymous
0

Step-by-step explanation:

2011–9 = 2002

2623–5 = 2618.

Factors of

2002 = 2 x7x11x13

2618 = 2x7x11x17

The HCF = 2 x7x11 = 154.

Check: 2011/154 = quotient = 13, and remainder = 9. Correct.

2623/154 = quotient = 17, and remainder = 5. Correct.

The number is 154.

Answered by priyarathore2006
0

Answer:

2002 and 2618

Step-by-step explanation:

2011-9=2002 and 2623-5=2615.

Similar questions